Follow by Email

Thursday, 28 November 2013

SPM 2013 Physics Paper 1 Answers

2013 SPM Physics Paper 1 Answers

Here are my answers - hopefully they are the same as the examiners': 

2 A
4 B
7 C
8 B
9 D
11 A
12 D
14 A
17 C
19 A
21 A
22 C
23 A
29 D
30 D
35 B
36 B
37 A
38 C
39 C
40 A
41 D
42 B
43 D
44 A
45 A
46 D
47 B
49 C
50 B

(My answers for SPM 2013 Chemistry Paper 1 can be viewed by clicking here.

My answers for SPM 2013 Modern Maths Paper 1 (1449/1) are here.)

My Comments on Some Physics P1 Questions:

Q 30: The answer is D. More than twice before, 'telescope at normal adjustment' was tested in SPM:
          * In 2005 P2 Q11(a)(iii) - diagram @ pg. 387 of Past-Yr Papers 2005-2012 - D;
          * In 2006 P2 Q9(c)(i) - diagram @ pg. 393 of Past-Yr Papers 2005-2012 - D; and,
          * see also pg. 299 of Oxford-Fajar (2013 Ed.) Fig 5.67 for telescope - Answer D!

Q32: The answer is D. Reason:

"As water waves enter shallower region (at headland first, then only the bay), their speed slows down with the shortening of wavelength (again at headland first, then only the bay) without any change in wave frequency. This refraction of water waves results in the wavefronts  taking the shape of the shoreline with wavelengths (distance between successive wavefronts) at the headland shorter than their corresponding wavelengths at the bay as shown by the diagram. At the bay, wave energy is spread-out over longer wavefronts resulting in calmer sea due to dispersal of wave energy. Answer: D

For many other questions, I have inserted some hotlinks which you can click on to direct you to the relevant pages of this blog where the answers can be found/deduced. For examples, if you click on the hotlink of:

* Q 33 D, you will be directed to the page on "Diffraction" where its Para 6 has the same diagram as in the answer D (but in different orientation);

* Q 32 D, you will be directed to the page on "Refraction of Waves" where its Para 7 shows similar diagram and the answer should be D;

* Q 31 C, you will be directed to the page on "Diffraction" where its Para 2 shows C should be the answer;

* Q 28 A, you will be directed to the page on "Refraction" where its Para 6, pt 1 shows you the answer;

* Q 27 A, you will be directed to the page on "Light" where its Para 2(d)(v)(2) shows you the answer;

* Q 26 A, you will be directed to the page on "Refraction" where its Para 6, pt 1 shows you the answer;

* Q 25 C, you will be directed to the page on "Refraction" where its 2nd Para 6 shows you the answer;
and, so on......


Need Help In Physics, Chemistry and Maths in or around Petaling Jaya?

Good News: Vacant tuition slots are now up for grab!

(June 18th, 2017):


Summer May/June 2017 IGCSE O-level and Edexcel O-level exams were just over. As such, some tuition slots are available for grabs on '1st-come-1st-serve" (3 slots have been taken). A few more slots are available for the following subjects:

* IGCSE: Math 0580 (Angela Loo, Absalom Wong, ... scored A's)
                Math 0606 (Nicole Gan scored A (83%), Kai Xun scored B* (79%) ...)
                International Maths 0607 (Zi Zhun waiting results - Switzerland-bound)
                Physics 0625 (Nicole Gan scored A* (93%), Lim Jin Quan A* (mark NA),...)
                Chemistry 0620; (Nicole Gan scored A* (94%), Lim Jin Quan A* (mark NA),...)

* Edexcel: Maths 4MAO / 4MBO / 4PMO (Previously taught 4MBO / 4PMO at Int'l Sch)
                 Chemistry 4CHO (Just tutored Ms. McLean Maths 4MAO, Chem n Physics)
                 Physics 4PHO (Ms. McLean waiting for results)

(CIE AS/A2: Chemistry 9701 / Physics 9702 can be considered if approached early)

Sms or whatsapp me Douglas at: 011-2120 1608; or,

Thank you.




Anonymous said...

48 is supposed to be A. Option for E is actually not avialable for physics paper 1

MR. Tan ( said...

Q48: At the end of 30 minutes (A), only 7/16 [=(1/4) + (1/4)(3/4)] of the radioactive substance has decayed. It takes another 6 minutes+ to decay a further 1/16 to reach half-life. Half-life = 36 minutes+. Therefore, Q48 has no acceptable answers. Click on the link Q48 E in the table of answers to see my write-up on Q48. Thk you.

Anonymous said...

why answer of Q32 is not B?
energy is focused at headland is true and wavelength at bay is shorter is also correct because bay is shallower.

MR. Tan ( said...

Q32 Answer D. Reason:

"When the wavefronts approach the shoreline, they reach the headland (cape) earlier than the bay because the cape represents the protruding part of the shoreline that becomes shallow earlier than the bay.
Therefore, the water waves near the headland or cape slow down first - thus, their wavelength becomes smaller or wavefronts become closer near the cape while those approaching the bay are still having greater wavelength and their wavefronts are still further apart i.e longer and NOT shorter. Ans. B is wrong; D is correct. :)

Anonymous said...

how to do question no.37?

Anonymous said...

why is q.4 B and not A?

MR. Tan ( said...

Sorry, this blog no longer entertains questions from anonymous. You must at least introduce yourself: occupation (student, parent teacher, tutor, etc.); location (KL, PJ, etc.); and anything else that may be of interest to readers of this blog (eg. currently preparing to sit for SPM 2014). Thank you.