1.
Electromotive
force V(e.m.f.) of an electrical source is defined as the work done (W) by the source in driving per unit charge around a complete circuit: V(e.m.f.) = W/Q = E/Q.
a. A complete circuit consists of both the internal (within the source) and the external circuits (outside the source):
a. A complete circuit consists of both the internal (within the source) and the external circuits (outside the source):
b.
An
electrical source can be a cell,
a battery or any other source of
electricity.
c.
A cell uses
chemical reaction to produce current – it converts chemical
energy to electrical energy. A cell produces one directional current known as
the DC current.
d.
A battery
is a combination of 2 or more cells in
series.
2.
Since it is energy that enables work to be done, electromotive force V(e.m.f.) can be
alternatively viewed as the electrical energy E
supplied or used by the source to drive per unit charge around a complete
circuit:
V(e.m.f.)
= W/Q = E/Q
V(e.m.f.)
= W/It (since, Q = It as I = Q/t)
V(e.m.f)
= P/I (since power P = W/t)
Therefore, electromotive force may also be defined as the ratio of the total power supplied to the whole circuit to the current flowing
through it.
3.
Electromotive
force V(e.m.f.) may be measured by:
i.
A high-resistance voltmeter: By measuring
the potential difference of the cell
or electrical source in an open circuit –
this is however not the true value
because a small current still flows through the voltmeter and part of the
electromotive force becomes part of the potential difference across the
voltmeter itself;
ii.
A cathode ray oscilloscope; or
iii.
A potentiometer.
4.
Experimental evidence (pg. 379) shows that:
i.
Electromotive
force V(e.m.f.) is (approximately) the potential
difference across the cell or source of electricity in an open circuit – when no current flows through the external
circuit or through any external components (Yr 2005 SPM P1 Q38 at pg. 11).
ii.
Electromotive
force V(e.m.f.) is not the same as terminal potential difference Vt – i.e. it is not equal to the potential difference across a closed external circuit through which
current is flowing:
V(e.m.f.)
> terminal potential difference Vt:
V(e.m.f) > Vt or Vt < V(e.m.f) …(Yr
2011 SPM P1 Q36 at pg. 288)
5. Lost volt or voltage drop (Vd) refers to: The difference between electromotive force E (or, V(e.m.f.) when circuit is open and terminal potential
difference Vt (when circuit is
closed) (Vd = V(e.m.f.) – Vt). Lost volt (Vd) is due to the internal
resistance r of the cell or electrical source:
V(emf) – Vt = + Vd; or
V(emf) = Vt + Vd; or
Vt = - Vd + V(emf); or
Vt = -rI + V(emf)...(This linear equation is analogous to y = mx + c, y = Vt; x = I; -r is the gradient m and V(e.m.f.) is the y-intercept of the linear graph)
Vt = -rI + V(emf)...(This linear equation is analogous to y = mx + c, y = Vt; x = I; -r is the gradient m and V(e.m.f.) is the y-intercept of the linear graph)
6.
The internal
resistance r of a cell is the resistance
within the cell or within the
internal circuit – that is, the resistance against the moving charge due to
the electrolyte.
7.
To show the existence
of internal resistance: A torch is switched on for, say, 20 minutes and the
dry cell in the torch becomes hot – due to internal resistance of the cell.
8.
Internal
resistance r can be found:
i.
By finding the voltage drop Vd over the current
I flowing when the circuit closed; or
(Yr 2007 SPM P1 Q37 at pg. 100) / (Yr 2010 SPM P1 Q41 at pg. 241); or
ii.
By finding the gradient of the Vt-I graph,
where Vt
= -rI + V(emf)
(as
in y = mx + c,
Where, V(emf) is the y-intercept; and
gradient m = internal resistance -r;
see the experiment to determine V(emf) and r using
the formula, Vt = -rI + V(emf) at pg. 381)
--------------------------------------------
Updated By: tutortan1@gmail.com (8/4/12)
No comments:
Post a Comment